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[DTube] Limit of sin(x)/x as x approaches 0: Geometric Proof


In this video, we work through a geometric proof for the limit of sin(x)/x as x approaches 0.

You may have visually inspected and tabulated that sin(x)/x does indeed approach L = 1 when x = 0, although the function is not defined at this point.

However, we need a more robust proof. And this is where this simple geometric proof, using the squeeze theorem can help us determine the limit of sin(x)/x as x approaches 0 formally.

Thanks for watching. Please give me a "thumbs up" if you have found this video helpful.

Please ask me a maths question by commenting below and I will try to help you in future videos.

I would really appreciate any small donation which will help me to help more math students of the world. Please donate here: https://paypal.me/MasterWu


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